表单脚本示例

流程表单

表单查看界面通过点击相应按钮跳转到审批表单

let currentFormParam = dataForm.getDataFormInfo();
if (currentFormParam.currentNodeName==='审批') {
  if (currentFormParam.formViewType === 'view') {
    dataForm.isHiddenButton('审批', true);
    dataForm.addButtonBefore('test审批',()=>{
      // 跳转审批表单
      dataForm.formInfo.showDataFormEditView()
    })
  } else if (currentFormParam.formViewType === 'edit') {
    dataForm.isHiddenButton('test审批', true);
  }
}

• 按钮前置查询

dataForm.addButtonBefore('提交', function (resolve, reject) {
    var formInfo = dataForm.getDataFormInfo();
    var id = formInfo.dataId;
    var userInfo = dataForm.$getUserInfo();
    var ParentName = userInfo.ParentName;

    // 使用参数化查询，避免 SQL 注入
    var query = "SELECT count(huifbm) AS replyCount FROM d_qljqyp_jqcl_h WHERE ParentObjectId = ? AND huifbm = ?";
    dataForm.$sql.select(query, [id, ParentName]).then(function (res) {
        if (res[0].replyCount > 0) {
            resolve();  // 如果有回复，继续提交
        } else {
            dataForm.$message({
                type: "warning",
                message: "请填写回复信息",
            });
            reject();  // 没有回复，阻止提交
        }
    }).catch(function (error) {
        dataForm.$message({
            type: "error",
            message: "查询失败，请稍后再试",
        });
        reject();  // 如果查询失败，阻止提交
        console.error(error);  // 打印错误，方便调试
    });
});